Simplification
- 10.8 x 5.5 x 8.4 = ?
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Multiply the given in question.
Correct Option: C
Multiply the given in question.
The answer would be
? = 10.8 x 5.5 x 8.4 = 498.96
- 8648 - 7652 = ? x 40
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Solve it by simple mathematics rule.
Correct Option: E
8648 - 7652 = ? x 40
996 = ? x 40 ⇒ ? = 996/40 = 24.9
- 683.46 - 227.39 - 341.85 = ?
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? = 683.46 - 227.39 - 341.85
= 683.46 - 569.24 = 114.22Correct Option: A
? = 683.46 - 227.39 - 341.85
= 683.46 - 569.24 = 114.22
- Mohan gets 3 marks for each correct sum and loses 2 marks for each wrong sum. He attempts 30 sums and obtains 40 marks. The number of sums solved correctly is
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Solution 1.
Let the question solved correctly by Mohan = X ;
and number of question solved wrongly by Mohan = 30 - X ;
According to the question,
3X - (30 - X) x 2 = 40
Solution 2.
Let the question solved correctly by Mohan = X ;
and number of question solved wrongly by Mohan = Y ;
According to given question;
X + Y = 30 ; and 3X - 2Y = 40 ;Correct Option: D
Solution 1.
Let the question solved correctly by Mohan = X ;
and number of question solved wrongly by Mohan = 30 - X ;
According to the question,
3X - (30 - X) x 2 = 40
⇒ 3x - 60 + 2x = 40
⇒ 5x - 60 = 40
⇒ 5x = 40 + 60 ⇒ x = 100/5 = 20
∴ Mohan attempted 20 questions correctly .
Solution 2.
Let the question solved correctly by Mohan = X ;
and number of question solved wrongly by Mohan = Y ;
According to given question;
X + Y = 30 ; -----------i
3X - 2Y = 40 ;-------ii
Now multiply the first equation by 2;
we will get
2X + 2Y = 60 ;--------iii
After Add the equation ii and iii , we will get
3X - 2Y + 2X + 2Y = 40 + 60 ;
⇒ 5X = 100 ;
⇒ X = 20;
∴ Mohan attempted 20 questions correctly .
- It is required to get 40% marks to qualify an exam. A candidate scored 200 marks and failed by 8 marks. What were the maximum marks of that exam?
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Let the maximum marks = x.
According to the question,
40x/100 = 200 + 8Correct Option: A
Let the maximum marks = x.
According to the question,
40x/100 = 200 + 8
⇒ x = 208 x 10/4 = 520