Sets and Functions


  1. In a class of 100 students, the number of students passed in English only is 46, in Maths only is 46, in Commerce only is 58. The number who passed in English and Maths is 16, Maths and Commerce is 24 and English and Commerce is 26, and the number who passed in all the subjects is 7. Find the number of the students who failed in all the subjects.









  1. View Hint View Answer Discuss in Forum

    Draw a figure and calculate.
    No. of students who passed in one or more subjects = 11 + 9 + 13 + 17 + 15 + 19 + 7 = 91.

    Correct Option: A

    No. of students who passed in one or more subjects = 11 + 9 + 13 + 17 + 15 + 19 + 7 = 91.
    No. of students who failed in all the subjects = 100 – 91 = 9.



  1. If A = {a, d}, B = {b, c, e} and C = {b, c, f}, then A × (B ∩ C) =










  1. View Hint View Answer Discuss in Forum

    As per given question,
    (B ∩ C) = {b, c, e} ∩ {b, c, f} = {b, c}
    ∴ A × (B ∩ C) = {a, d} × {b, c}
    = {(a, b), (a, c), (d, b), (d, c)}

    Correct Option: B

    Given in the question, we can can calculate,
    (B ∩ C) = {b, c, e} ∩ {b, c, f} = {b, c}
    ∴ A × (B ∩ C) = {a, d} × {b, c}
    = {(a, b), (a, c), (d, b), (d, c)}
    Also, (A × B) ∩ (A × C)
    = {(a, b), (a, c), (a, b), (d, c)}
    ∴ A × (B ∩ C) = (A × B) ∩ (A × C).



  1. If A = {a, b}, B = {2, 3, 5, 6, 7} and C = {5, 6, 7, 8, 9}, find A × (B ∩ C).









  1. View Hint View Answer Discuss in Forum

    We have,
    (B ∩ C) = {2, 3, 5, 6, 7} ∩ {5, 6, 7, 8, 9}
    = {5, 6, 7}

    Correct Option: D

    We have,
    (B ∩ C) = {2, 3, 5, 6, 7} ∩ {5, 6, 7, 8, 9}
    = {5, 6, 7}
    ∴ A × (B ∩ C) = {a, b} × {5, 6, 7}
    = {(a, 5), (a, 6), (a, 7), (b, 5), (b, 6), (b, 7)}.


  1. If A = {a, d}, B = {b, c, e} and C = {b, c, f}, then A × (B - C) =









  1. View Hint View Answer Discuss in Forum

    we can calculate below as per given question,
    (B − C) = { b, c, e } – { b, c, f } = { e }
    A × (B − C) = { a, d } x { e }
    (A × B) = { a, d } x { b, c, e }
    (A × C) = { a, d } x { b, c, f }

    Correct Option: A

    we can calculate below as per given question,
    we can calculate below as per given question,
    (B − C) = { b, c, e } – { b, c, f } = { e }
    A × (B − C) = { a, d } x { e }
    (A × B) = { a, d } x { b, c, e }
    (A × C) = { a, d } x { b, c, f }
    ∴ A × (B − C) = {(a, e), (d, e)} ...........…(1)
    Also, (A × B) – (A × C) = {(a, e), (d, e)} ..........…(2)
    Hence, from (1) and (2), we have
    A × (B − C) = (A × B) – (A × C).



  1. If U = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11},
    A = {2, 4, 7},
    B = {3, 5, 7, 9, 11} and
    C = {7, 8, 9, 10, 11}.
    compute: (A ∩ U) ∩ (B ∪ C)









  1. View Hint View Answer Discuss in Forum

    A ∩ U = {2, 4, 7} ∩ {2, 3, 4, 5, 6, 7, 8, 9, 10, 11}
    B ∪ C = {3, 5, 7, 9, 11} ∪ {7, 8, 9, 10, 11}.
    Then (A ∩ U) ∩ (B ∪ C) = {2, 4, 7,} ∩ {3, 5, 7, 8, 9, 10, 11}

    Correct Option: A

    A ∩ U = {2, 4, 7} ∩ {2, 3, 4, 5, 6, 7, 8, 9, 10, 11}
    A ∩ U = {2, 4, 7};
    B ∪ C = {3, 5, 7, 9, 11} ∪ {7, 8, 9, 10, 11}.
    B ∪ C = {3, 5, 7, 8, 9, 10, 11}.
    Then (A ∩ U) ∩ (B ∪ C) = {2, 4, 7,} ∩ {3, 5, 7, 8, 9, 10, 11}
    (A ∩ U) ∩ (B ∪ C) = {7}.