Profit and Loss
- A person sold a table at a gain of 15%. Had he bought it for 25% less and sold it for ₹ 60 less, he would have made a profit of 32%. The cost price of table was
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Let the cost price of table = ₹ N
Then, selling price with 15% gain
= (100 + Gain%) x CP/100
= (100 + 15)% x CP/100
= (115 x N)/100 = ₹ 115N/100
Now CP = [(100 - 25%) x CP]/100 = ₹ 75N/100
New SP = ₹ (115N/100) - 60
Now, according to the question,
[[(115/100 )- 60) - (75N/100)]/ (75N/100)] x 100 = 32Correct Option: C
Let the cost price of table = ₹ N
Then, selling price with 15% gain
= (100 + Gain%) x CP/100
= (100 + 15)% x CP/100
= (115 x N)/100 = ₹ 115N/100
Now CP = [(100 - 25%) x CP]/100 = ₹ 75N/100
New SP = ₹ (115N/100) - 60
Now, according to the question,
[[(115/100 )- 60) - (75N/100)]/ (75N/100)] x 100 = 32
⇒ [[(115N - 6000 - 75N)/100 ]/ (75N/100)] x 100 = 32
⇒ [(40N - 6000)/75N] x 100 =32
⇒ (40N - 6000)/(3N x 4) = 32
⇒ 160N - 24000 = 96N
⇒ 160N - 96N = 24000
⇒ 64N = 24000
⇒ N = 24000/64
⇒ N = ₹ 375
∴ The cost price of table is ₹ 375.
- A person bought two bicycles for ₹ 1600 and sold the first at 10% profit and the second at 20% profit. If he sold the first at 20% profit and the second at 10% profit, he would get ₹ 5 more. The difference in the cost price of the two bicycles was
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Let the cost price of first bicycle be ₹ P.
Then, the cost price of second bicycle = ₹ (1600 - P)
According to the given condition,
[20% of P + 10% of (1600 - P )] - [10% of P + 20% of (1600 - P)] = 5
⇒ [(20P/100) + [10 x (1600 - P)]/100] - [(10P/100) + {20 x (1600 - P)}/100] = 5
⇒ (P/5 + (1600 - P)/10) - (P/10 + (1600 - P)/5) = 5Correct Option: C
Let the cost price of first bicycle be ₹ P.
Then, the cost price of second bicycle = ₹ (1600 - P)
According to the given condition,
[20% of P + 10% of (1600 - P )] - [10% of P + 20% of (1600 - P)] = 5
⇒ [(20P/100) + [10 x (1600 - P)]/100] - [(10P/100) + {20 x (1600 - P)}/100] = 5
⇒ (P/5 + (1600 - P)/10) - (P/10 + (1600 - P)/5) = 5
⇒ P/5 - P/10 + (1600 - P)/10 - (1600 - P)/5 = 5
⇒ 2P = 1600 + 50
∴ P = 1650/2 = 825
∴ Cost of second bicycle = (1600 - 825) = ₹ 775
∴ Required difference = 825 - 775 = ₹ 50
- A retailer increase the selling price by 25% due to which his profit percentage increases from 20% to 25%. What is the percentage increase in cost price ?
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In beginning
Cost Price (CP) = Rs. 100
Profit % = 20
Selling Price (SP) = 120
When profit increases from 20% to 25%
Cost Price (CP) = y
Profit % = 25
Selling Price (SP) after 25% increase = 120 + 25% = Rs. 150Correct Option: A
In beginning
Cost Price (CP) = Rs. 100
Profit % = 20
Selling Price (SP) = 120
When profit increases from 20% to 25%
Cost Price (CP) = y
Profit % = 25
Selling Price (SP) after 25% increase = 120 + 25% = Rs. 150
From question
y + 25 % profit = 150
1.25 y = 150
so y = 120
% change in cost price = [ (120 - 100) / 100 ] x 100 = 20%
- Anupam sells a painting to Bhargava at 4/5th the rate of profit at which Bhargava sells it to Chaudhary. Further Chaudhary sells it to Dara Singh at half the rate of profit at which Anupam sold it to Bhargava. If Chaudhary earns a profit of 10% by selling it to Dara Singh for Rs. 2805. What is the cost price of painting from Bhargava?
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From question Chaudhary's profit = 10%.
So, Anupam's profit = 20%
Bhargava profit = 25%
Now Let cost price for Anupam = Rs. 100
So cost price for Bhargava = 120
Cost price for Chaudhary = 150
Cost price for Dara Singh = 165Correct Option: B
From question, Chaudhary's profit = 10%.
So, Anupam's profit = 20%
Bhargava profit = 25%
Now Let cost price for Anupam = Rs. 100
So cost price for Bhargava = 120
Cost price for Chaudhary = 150
Cost price for Dara Singh = 165
Since the cost price for Dara singh is 2805 which is 17 times of 165. So the cost price for Bhargava is 120 x 17 = Rs. 2040.
- Jhun Jhunwala makes 1000 toys and incurs a cost of Rs. 1.2 for each toy. He marks-up the price in such a way that if he sells only 70% of manufactured toys he will realize 16.66% overall profit. He sells only 750 articles at the marked price since rest of the toys are found to be defective so can't be sold. What is the net profit or loss of Jhun Jhunwala?
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Total cost price = 1000 x 1.2 = Rs. 1200
Expected selling price = 700 x selling price per toys = 1200 X 1.1666 = 1400
→ Selling price per toys = Rs. 2 per toyCorrect Option: B
Total cost price = 1000 x 1.2 = Rs. 1200
Expected selling price = 700 x selling price per toys = 1200 X 1.1666 = 1400
→ Selling price per toys = Rs. 2 per toy
Now the real selling price = 750 x 2 = Rs.1500
∴ Profit = Rs. 300 = (1500 - 1200)
∴ Profit % = ( 300 / 1200 ) x 100 = 25%
