Fractions

Fractions

Easy Questions
Moderate Questions
Difficult Questions
Fractions Tutorial

Aptitude

Simplification
Number System
Fractions
Elementary Algebra
LCM and HCF
Approximation
Unitary Method
Linear Equation
Quadratic Equation
Discount
Average
Surds and Indices
Percentage
Square root and cube root
Order of Magnitude
Work and Wages
Odd Man Out and Series
Algebra
Profit and Loss
Stocks and Shares
True Discount
Ratio, Proportion
Partnership
Alligation or Mixture
Time and Work
Pipes and Cistern
Speed, Time and Distance
Problem on Trains
Height and Distance
Banker's Discount
Boats and Streams
Races and games
Problems on Ages
Clocks and Calendars
Simple interest
Compound Interest
Sets and Functions
Area and Perimeter
Volume and Surface Area of Solid Figures
Sequences and Series
Plane Geometry
Logarithm
Probability
Permutation and Combination
Statistics
Mensuration
Trigonometry
Aptitude miscellaneous
  1. If 0.3+ 0.6 + 0.7 + 0.8 = x, then x is equal to ?








  1. View Hint View Answer Discuss in Forum

    0.3+ 0.6 + 0.7 + 0.8 = x,
    ⇒ x = 3/9 + 6/9 + 7/9 + 8/9 = 24/9 = 8/3

    Correct Option: B

    0.3+ 0.6 + 0.7 + 0.8 = x,
    ⇒ x = 3/9 + 6/9 + 7/9 + 8/9 = 24/9 = 8/3 = 22/3

  1. From a rope 30 m long, a person cuts off as many pieces as possible, each 31/4 m long. What fraction of the whole will be left ?








  1. View Hint View Answer Discuss in Forum

    Length of each piece = 31/4 = 13/4 m
    Maximum pieces that can be cut = 30/(13/4) = 9
    ∴ Rope left = 30 - 13/4 x 9 = 120 - 117/4 = 3/4 m
    ∴ Required fraction = 3/4/30 = 1/4

    Correct Option: A

    Length of each piece = 31/4 = 13/4 m
    Maximum pieces that can be cut = 30/(13/4) = 9
    ∴ Rope left = 30 - 13/4 x 9 = 120 - 117/4 = 3/4 m
    ∴ Required fraction = 3/4/30 = 1/4

  1. A scooter before overhauling requires 2/3 h service time every 45 days,while after overhauling it requires 2/3 h service time every 60 days. what fraction of pre-overhauling service time is saved in the latter case ?








  1. View Hint View Answer Discuss in Forum

    Time required for service before overhauling = 2/3h = 40 min in 45 days
    and time required for service after overhualing =2/3h= 40 min in 60 days
    Now,LCM of 45 and 60 = 180 days
    time required for service before overhauling is 180 days = 40 x

    Correct Option: D

    Time required for service before overhauling = 2/3h = 40 min in 45 days
    and time required for service after overhualing =2/3h= 40 min in 60 days
    Now,LCM of 45 and 60 = 180 days
    time required for service before overhauling is 180 days = 40 x 4 = 160 min
    and time required for service before overhauling is 180 days =40 x 3 = 120 min
    ∴ fraction of time saved = 160 - 120/160 =40/160 = 1/4

  1. (1/4)th of number of boys and (3/8)th of number of girls participated in annual sport days in the school. What fractional part of total number of students participated ?








  1. View Hint View Answer Discuss in Forum

    Total number of students participated = (B/4 + 3G/4)
    ∴ Required percentage= (B/4 + 3G/4) / (B+G) x 100%

    Correct Option: D

    Total number of students participated = (B/4 + 3G/4)
    ∴ Required percentage= (B/4 + 3G/4) / (B+G) x 100%
    Clearly, given data is inadequate.

  1. In a village, (5/8)th of the population are adults,half of the adults are male,(4/5)th of adult females are illiterate. if 400 females are illiterate, then the population of the village is ?








  1. View Hint View Answer Discuss in Forum

    Let the population of village = N
    Then, adult's population = 5N/8
    and adult females = 1/2 x 5N/8 = 5N/16
    ∴ illiterate females = 4/5 of adult female population
    ⇒ 400 = 4/5 x 5N/16

    Correct Option: D

    Let the population of village = N
    Then, adult's population = 5N/8
    and adult females = 1/2 x 5N/8 = 5N/16
    ∴ illiterate females = 4/5 of adult female population
    ⇒ 400 = 4/5 x 5N/16
    ⇒ N = (400 x 16)/4
    ∴ N = 1600