Clocks and Calendars


  1. January 16, 1997 was a Thursday. What day of the week will it be on January 4, 2000 ?









  1. View Hint View Answer Discuss in Forum

    First we look for the leap years during this period 1997, 1998, 1999 are not leap years.
    1998 and 1999 together have net 2 odd days No. of days remaining in 1997 = 365 - 16 = 349 days = 49 week 6 odd days
    January 4, 2000 gives 4 odd days.
    ∴ Total no. of days = 2 + 6 + 4 = 12 days = 7 Days (1 week) + 5 odd days

    Correct Option: A

    First we look for the leap years during this period 1997, 1998, 1999 are not leap years.
    1998 and 1999 together have net 2 odd days No. of days remaining in 1997 = 365 - 16 = 349 days = 49 week 6 odd days
    January 4, 2000 gives 4 odd days.
    ∴ Total no. of days = 2 + 6 + 4 = 12 days = 7 Days (1 week) + 5 odd days

    Hence, January 4, 2000 will be 5 days beyond Thursday i.e., it will on Tuesday.


  1. P.V. Narsihma Rao was elected party leader on 29th may, 1991. What was the day of the week ?









  1. View Hint View Answer Discuss in Forum

    Try yourself. It was Wednesday.

    Correct Option: C

    Try yourself. It was Wednesday.



  1. A clock is set right at 10 am. The clock gain 10 min in a day. What will be the true time when the watch indicates 3 pm the next day ?









  1. View Hint View Answer Discuss in Forum

    Time from 10 am to 3 pm of the next day = 29 h
    Now, 24 h 10 min of the clock in question = 24 h of the correct clock

    Correct Option: C

    Time from 10 am to 3 pm of the next day = 29 h
    Now, 24 h 10 min of the clock in question = 24 h of the correct clock
    i.e., 145 h of the clock in question = 24 h of the correct clock
    29 h of the clock in question = 24 x (6/145) x 29) h of correct clock = 28 h 48 min correct clock
    So, the correct time is 28 h 48 min after 10 am i.,e 48 min past 2 pm.


  1. Calendar for the year 2008 will be the same for which of the following years ?











  1. View Hint View Answer Discuss in Forum

    Count the number of odd days from the year 2008 onward to get the sum equal to 0 odd day.

    Correct Option: B

    Count the number of odd days from the year 2008 onward to get the sum equal to 0 odd day.

    Let us see
    2008 = 2
    2009 = 1
    2010 = 1
    2011 = 1
    2012 = 2
    2013 = 1
    2014 = 1
    2015 = 1
    2016 = 2
    2017 = 1
    2018 = 1

    Sum = 2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 + 1 = 14 days = 2 weeks = 0 odd days
    ∴ Calendar for the year 2019 will be the same as for the year 2008



  1. At what time between 5 o'clock and 6 o'clock in the morning, will the both hands of a clock of a clock be at right angle?











  1. View Hint View Answer Discuss in Forum

    Given that n = 5 and n + 1 = 6
    The hands will make right angle at
    (5n ± 15) x 12/11 min past 5 .

    Correct Option: B

    Given that n = 5 and n + 1 = 6
    The hands will make right angle at
    (5n ± 15) x 12/11 min past 5 .
    ⇒ (5 x 5 ± 15) x 12/11 min past 5.
    ⇒ (25 + 15) x 12/11 min past 5 and (25 - 15) x 12/11 min past 5.
    ⇒ 40 x 12/11 min past 5 and 10 x 12/11 min past 5.
    ⇒ 4801/11 min past 5 and 120/11 min past 5.
    ⇒ 437/11 min past 5 and 1010/11 min past 5.