Here, n = 3 and (n + 1) = 4
∴ Two hands will coincide at 60n / 11 min past n

Correct Option: D

Here, n = 3 and (n + 1) = 4
∴ Two hands will coincide at 60n / 11 min past n
⇒ 60 x 3 / 11 min past 3
⇒ 180 /11 min past 3.
⇒ 16⁴/Sub>11 min past 3

A leap year must be divisible by 4 as every 4th year is a leap year..

Correct Option: D

A leap year must be divisible by 4 as every 4th year is a leap year..

Find the number of odd or even days of consequent years..

Correct Option: D

For two years having same calendar must have two common conditions: both having same length in terms of number of days and first day of the week.

The year 1991 has 365 days,,that is 1 odd day , year 1992 has 366 days , i.e. 2 odd days , year 1993 has 365 days i.e. 1 odd day. the years 1994,1995,1996 have 1 odd day each.

the sum of odd days so calculated from year 1990 to 1996 .
(1+2+1+1+1+1)=7 odd days. 5

hence, the year 1997 will have same calendar as that of year 1990.

The century year which is completely divisible by 400, is a leap year.

Correct Option: A

The century year which is completely divisible by 400, is a leap year. Thus, the year 2800 is a leap year.

Angle traced by hour hand in 12 h = 360°

Correct Option: A

Angle traced by hour hand in 12 h = 360°
Angle traced by hour hand in 5 h = (360/12) x 5° = 150°