The year 1984 being a leap year, it has 2 odd days. So, the day on 2nd July, 1985 is two days beyond the day on 2nd July, 1984. But, 2nd July 1985 was Wednesday.

Correct Option: C

The year 1984 being a leap year, it has 2 odd days. So, the day on 2nd July, 1985 is two days beyond the day on 2nd July, 1984. But, 2nd July 1985 was Wednesday.

∴ 2nd July, 1984 was Monday

No of days = Jan. + Feb. + March
30 + 28 + 15 = 73 days

Correct Option: B

No of days = Jan. + Feb. + March
30 + 28 + 15 = 73 days

Starting with 1988, we go on counting thye number of odd days till the sum is divisible by 7
Year 1988 odd days = 2
Year 1989 odd days = 1
Year 1990 odd days = 1
Year 1991 odd days = 1
Year 1992 odd days = 2

So total odd days = 7;
∴ Calendar for 1993 is the same as that of 1988.

Correct Option: C

Starting with 1988, we go on counting thye number of odd days till the sum is divisible by 7
Year 1988 odd days = 2
Year 1989 odd days = 1
Year 1990 odd days = 1
Year 1991 odd days = 1
Year 1992 odd days = 2

So total odd days = 7;
∴ Calendar for 1993 is the same as that of 1988.

A leap year has (52 week + 2 days).

Correct Option: B

A leap year has (52 week + 2 days).
So, the number of odd days in a leap year is 2

Total hours 6 : 14 am morning to evening 6 : 14 pm = 12 h
and total hours from 6 : 14 pm evening to 8 : 02 pm evening = 8 : 02 - 6 : 14 = 1 : 18 h i.e., 1 h and 48 min

Correct Option: C

Total hours 6 : 14 am morning to evening 6 : 14 pm = 12 h
and total hours from 6 : 14 pm evening to 8 : 02 pm evening = 8 : 02 - 6 : 14 = 1 : 18 h i.e., 1 h and 48 min
∴ Total hours and minutes = 12 h + 1 h 48 min
= 13 h and 48 min