## Clocks and Calendars

#### Clocks and Calendars

1. The year next to 1991 will have the same calender as that of the year 1991.
1. 1992
2. 1995
3. 1996
4. 1997

1. Find the number of odd or even days of consequent years..

##### Correct Option: D

For two years having same calendar must have two common conditions: both having same length in terms of number of days and first day of the week.

The year 1991 has 365 days,,that is 1 odd day , year 1992 has 366 days , i.e. 2 odd days , year 1993 has 365 days i.e. 1 odd day. the years 1994,1995,1996 have 1 odd day each.

the sum of odd days so calculated from year 1990 to 1996 .
(1+2+1+1+1+1)=7 odd days. 5

hence, the year 1997 will have same calendar as that of year 1990.

1. Today is Friday. After 62 days it will be ?
1. Friday
2. Thursday
3. Saturday
4. Monday

1. Each day of the week is repeated after 7 days
∴ After 63 days, it would be Friday
So, After 62 days, it would be Thursday

##### Correct Option: B

Each day of the week is repeated after 7 days
∴ After 63 days, it would be Friday
So, After 62 days, it would be Thursday

1. On July, 2, 1985, it was Wednesday the day of the week on July 2, 1984 was ?
1. Wednesday
2. Tuesday
3. Monday
4. Thurdays

1. The year 1984 being a leap year, it has 2 odd days. So, the day on 2nd July, 1985 is two days beyond the day on 2nd July, 1984. But, 2nd July 1985 was Wednesday.

##### Correct Option: C

The year 1984 being a leap year, it has 2 odd days. So, the day on 2nd July, 1985 is two days beyond the day on 2nd July, 1984. But, 2nd July 1985 was Wednesday.

∴ 2nd July, 1984 was Monday

1. How many days are three from 2nd January 1993 to 15th march 1993 ?
1. 72
2. 73
3. 74
4. 71

1. No of days = Jan. + Feb. + March
30 + 28 + 15 = 73 days

##### Correct Option: B

No of days = Jan. + Feb. + March
30 + 28 + 15 = 73 days

1. The year next to 1990 having the same calender as 1998 is ?
1. 1990
2. 1992
3. 1993
4. 1995

1. Starting with 1988, we go on counting thye number of odd days till the sum is divisible by 7
Year 1988 odd days = 2
Year 1989 odd days = 1
Year 1990 odd days = 1
Year 1991 odd days = 1
Year 1992 odd days = 2

So total odd days = 7;
∴ Calendar for 1993 is the same as that of 1988.

##### Correct Option: C

Starting with 1988, we go on counting thye number of odd days till the sum is divisible by 7
Year 1988 odd days = 2
Year 1989 odd days = 1
Year 1990 odd days = 1
Year 1991 odd days = 1
Year 1992 odd days = 2

So total odd days = 7;
∴ Calendar for 1993 is the same as that of 1988.