Average


  1. A cricketer has a certain average for 10 inning. In the eleventh innings. he scored 216 runs, there by increasing his average by 12 runs. Find out his new average?











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    Let average after 10th innings = x.
    According to the question.
    10x + 216 = 11(x +12)

    Correct Option: A

    Let average after 10th innings = x.
    According to the question.
    10x + 216 = 11(x +12)
    ⇒ x = 216 - 132 = 84
    ∴ New average = 84 + 12 = 96


  1. A cricketer whose bowling average is 12.4 runs per wicket, takes 5 wickets for 26 runs and there by decreases his average by 0.4. Find out the number of wickets taken by him till the last match ?











  1. View Hint View Answer Discuss in Forum

    Let x be the number of wickets taken till the last match
    According to the question,
    (12.4 x + 26) = 12(x + 5)

    Correct Option: C

    Let x be the number of wickets taken till the last match
    According to the question,
    (12.4 x + 26) = 12(x + 5)
    ⇒ 12.4 x + 26 = 12x + 60
    ⇒ 0.4 x = 34
    ∴ x = 34/0.4 = 85



  1. The average age of two boys and their father is greater then average age of those two boys and their mother by 3 yr. The average age of the four is 19 yr. If the average age of the two boys be 51/2, then find the age of the father and mother.









  1. View Hint View Answer Discuss in Forum

    Let the ages of mother, father and boys be M, F, B1 and B2, respectively.
    The total age of four member
    = 19 x 4
    = 76 yr.

    Given (B1 + B1)/2 = 11/2
    ⇒ B1 + B2 = 11
    M + F + B1 + B2 = 76 - 11
    ⇒ M + F = 65 .......(i)

    According to the question,
    (B1 + B2 + F) / 3 = (B1 + B2 + M) / 3 + 3

    Correct Option: A

    Let the ages of mother, father and boys be M, F, B1 and B2, respectively.
    The total age of four member
    = 19 x 4
    = 76 yr.

    Given (B1 + B1)/2 = 11/2
    ⇒ B1 + B2 = 11
    M + F + B1 + B2 = 76 - 11
    ⇒ M + F = 65 .......(i)

    According to the question,
    (B1 + B2 + F) / 3 = (B1 + B2 + M) / 3 + 3
    ⇒ B1 + B2 + F) = B1 + B2 + M + 9
    ⇒ F = M + 9
    ⇒ F - M = 9 ............. (ii)

    From Eqs (i) and (ii), we get
    F = 37 yr and M = 28 yr


  1. A has double the money of B and B has 50% more money then C. If average money of all the three persons is ₹ 12000, how money does A have ?











  1. View Hint View Answer Discuss in Forum

    Let money of C be ₹ N.

    According to the question
    Total money of B = N + N x 50%
    = N + 50N/100 = 3N/2

    Total money of A = 2 x 3N/2 = 3N

    Average money of three persons = 12000
    ∴ Total money of three = 12000 x 3
    ∴ 3N + (3N/2) + N = 12000 x 3

    Correct Option: C

    Let money of C be ₹ N.

    According to the question
    Total money of B = N + N x 50%
    = N + 50N/100 = 3N/2

    Total money of A = 2 x 3N/2 = 3N

    Average money of three persons = 12000
    ∴ Total money of three = 12000 x 3
    ∴ 3N + (3N/2) + N = 12000 x 3
    ⇒ (6N + 3N + 2N)/2 = 36000
    ∴ N = (36000 x 2)/11 = 72000/11

    Now, money of A = 3N = (3 x 72000)/11
    = ₹ 216000/11



  1. A cricketer played 80 innings and scored an average of 99 runs. His score in the last inning is zero run. To have an average of 100 at the end, his score in the last innings should have been.









  1. View Hint View Answer Discuss in Forum

    Let the required runs be N.

    According to the question,
    (80 x 99 + N) / 80 = 100

    Correct Option: D

    Let the required runs be N.

    According to the question,
    (80 x 99 + N) / 80 = 100
    ⇒ 7920 + N = 8000
    ⇒ N = 80