Average


  1. The average monthly salary of 19 members of a group is Rs. 16000. If one more member whose monthly salary is Rs. 20000 joins the group, then the average salary of the group is









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    The average monthly salary of 19 members of a group = Rs. 16000.
    A member whose monthly salary = Rs. 20000

    Required average = Rs.
    16000 × 19 + 20000
    20

    Required average = Rs.
    304000 + 20000
    20

    Required average = Rs.
    324000
    20

    Required average = Rs. 16200
    Second method to solve this question ,
    Difference = Rs. (20000 – 16000) = Rs. 4000

    Correct Option: B

    The average monthly salary of 19 members of a group = Rs. 16000.
    A member whose monthly salary = Rs. 20000

    Required average = Rs.
    16000 × 19 + 20000
    20

    Required average = Rs.
    304000 + 20000
    20

    Required average = Rs.
    324000
    20

    Required average = Rs. 16200
    Second method to solve this question ,
    Difference = Rs. (20000 – 16000) = Rs. 4000
    ∴ Increase in average =
    4000
    20

    Increase in average = Rs. 200
    ∴ Required average = Rs. (16000 + 200) = Rs. 16200


  1. Three Science classes A, B and C take a Life Science test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. Then the average score of classes A, B and C is









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    Let Students in class A ⇒ p
    Students in class B ⇒ q
    Students in class C ⇒ r
    For classes A and B,

    83p + 76q
    = 79
    p + q

    ⇒ 83p + 76q = 79p + 79q
    ⇒ 83p – 79p = 79q – 76q
    ⇒ 4p = 3q
    For classes B and C
    76q + 85r
    = 81
    q + r

    ⇒ 76q + 85r = 81q + 81r
    ⇒ 5q = 4r
    ∴ 20p = 15q = 12r
    20p
    =
    15q
    =
    12r
    606060

    p
    =
    q
    =
    r
    345

    Required average =
    83 × 3 + 76 × 4 + 85 × 5
    3 + 4 + 5

    Correct Option: A

    Let Students in class A ⇒ p
    Students in class B ⇒ q
    Students in class C ⇒ r
    For classes A and B,

    83p + 76q
    = 79
    p + q

    ⇒ 83p + 76q = 79p + 79q
    ⇒ 83p – 79p = 79q – 76q
    ⇒ 4p = 3q
    For classes B and C
    76q + 85r
    = 81
    q + r

    ⇒ 76q + 85r = 81q + 81r
    ⇒ 5q = 4r
    ∴ 20p = 15q = 12r
    20p
    =
    15q
    =
    12r
    606060

    p
    =
    q
    =
    r
    345

    Required average =
    83 × 3 + 76 × 4 + 85 × 5
    3 + 4 + 5

    Required average =
    249 + 304 + 425
    12

    Required average =
    978
    12

    Required average = 81.5



  1. The average weight of first 11 persons among 12 persons is 95 kg. The weight of 12th person is 33 kg more than the average weight of all the 12 persons. The weight of the 12th person is









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    Let Weight of 12th person = w kg

    ∴ Average weight of 12 persons =
    11 × 95 + w
    kg
    12

    According to the question,

    Correct Option: C

    Let Weight of 12th person = w kg

    ∴ Average weight of 12 persons =
    11 × 95 + w
    kg
    12

    According to the question,
    ⇒ w =
    11 × 95 + w
    + 33 = w
    12

    ⇒ 1045 + w + 396 = 12w
    ⇒ 1441 = 11w
    ⇒ w =1441/11 = 131 kg.


  1. The average of 30 numbers is 40 and that of other 40 numbers is 30. The average of all the numbers is









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    ∴ Average of all numbers =
    30 × 40 + 40 × 30
    70

    Average of all numbers =
    240
    7

    Average of all numbers = 342
    7

    Second method to find the required average ,
    Here, n1 = 30, a1 = 40
    n2 = 40, a2 = 30
    ∴ Average =
    n1a1 + n2a2
    n1 + n2

    Correct Option: A

    ∴ Average of all numbers =
    30 × 40 + 40 × 30
    70

    Average of all numbers =
    240
    7

    Average of all numbers = 342
    7

    Second method to find the required average ,
    Here, n1 = 30, a1 = 40
    n2 = 40, a2 = 30
    ∴ Average =
    n1a1 + n2a2
    n1 + n2

    ∴ Average =
    30 × 40 + 40 × 30
    70

    Average =
    240
    7

    Average = 342
    7



  1. A library has an average number of 510 visitors on Sunday and 240 on other days. The average number of visitors per day in a month of 30 days beginning with Sunday is :









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    That month will have 5 sundays.

    ∴ Required average =
    5 × 510 + 25 × 240
    40

    Required average =
    2550 + 6000
    30

    Required average =
    8550
    = 285
    30

    Second method to find the required average ,
    Here,
    n1 = 5, a1 = 510
    n2 = 25, a2 = 240
    ∴ Average =
    n1a1 + n2a2
    n1 + n2

    Correct Option: A

    That month will have 5 sundays.

    ∴ Required average =
    5 × 510 + 25 × 240
    40

    Required average =
    2550 + 6000
    30

    Required average =
    8550
    = 285
    30

    Second method to find the required average ,
    Here,
    n1 = 5, a1 = 510
    n2 = 25, a2 = 240
    ∴ Average =
    n1a1 + n2a2
    n1 + n2

    Average =
    5 × 510 + 25 × 240
    40

    Average =
    2550 + 6000
    30

    Average =
    8550
    = 285
    30