Average
- The average monthly salary of 19 members of a group is Rs. 16000. If one more member whose monthly salary is Rs. 20000 joins the group, then the average salary of the group is
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The average monthly salary of 19 members of a group = Rs. 16000.
A member whose monthly salary = Rs. 20000Required average = Rs. 16000 × 19 + 20000 20 Required average = Rs. 304000 + 20000 20 Required average = Rs. 324000 20
Required average = Rs. 16200
Second method to solve this question ,
Difference = Rs. (20000 – 16000) = Rs. 4000
Correct Option: B
The average monthly salary of 19 members of a group = Rs. 16000.
A member whose monthly salary = Rs. 20000Required average = Rs. 16000 × 19 + 20000 20 Required average = Rs. 304000 + 20000 20 Required average = Rs. 324000 20
Required average = Rs. 16200
Second method to solve this question ,
Difference = Rs. (20000 – 16000) = Rs. 4000∴ Increase in average = 4000 20
Increase in average = Rs. 200
∴ Required average = Rs. (16000 + 200) = Rs. 16200
- Three Science classes A, B and C take a Life Science test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. Then the average score of classes A, B and C is
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Let Students in class A ⇒ p
Students in class B ⇒ q
Students in class C ⇒ r
For classes A and B,83p + 76q = 79 p + q
⇒ 83p + 76q = 79p + 79q
⇒ 83p – 79p = 79q – 76q
⇒ 4p = 3q
For classes B and C76q + 85r = 81 q + r
⇒ 76q + 85r = 81q + 81r
⇒ 5q = 4r
∴ 20p = 15q = 12r⇒ 20p = 15q = 12r 60 60 60 ⇒ p = q = r 3 4 5 Required average = 83 × 3 + 76 × 4 + 85 × 5 3 + 4 + 5
Correct Option: A
Let Students in class A ⇒ p
Students in class B ⇒ q
Students in class C ⇒ r
For classes A and B,83p + 76q = 79 p + q
⇒ 83p + 76q = 79p + 79q
⇒ 83p – 79p = 79q – 76q
⇒ 4p = 3q
For classes B and C76q + 85r = 81 q + r
⇒ 76q + 85r = 81q + 81r
⇒ 5q = 4r
∴ 20p = 15q = 12r⇒ 20p = 15q = 12r 60 60 60 ⇒ p = q = r 3 4 5 Required average = 83 × 3 + 76 × 4 + 85 × 5 3 + 4 + 5 Required average = 249 + 304 + 425 12 Required average = 978 12
Required average = 81.5
- The average weight of first 11 persons among 12 persons is 95 kg. The weight of 12th person is 33 kg more than the average weight of all the 12 persons. The weight of the 12th person is
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Let Weight of 12th person = w kg
∴ Average weight of 12 persons = 11 × 95 + w kg 12
According to the question,
Correct Option: C
Let Weight of 12th person = w kg
∴ Average weight of 12 persons = 11 × 95 + w kg 12
According to the question,⇒ w = 11 × 95 + w + 33 = w 12
⇒ 1045 + w + 396 = 12w
⇒ 1441 = 11w
⇒ w =1441/11 = 131 kg.
- The average of 30 numbers is 40 and that of other 40 numbers is 30. The average of all the numbers is
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∴ Average of all numbers = 30 × 40 + 40 × 30 70 Average of all numbers = 240 7 Average of all numbers = 34 2 7
Second method to find the required average ,
Here, n1 = 30, a1 = 40
n2 = 40, a2 = 30∴ Average = n1a1 + n2a2 n1 + n2
Correct Option: A
∴ Average of all numbers = 30 × 40 + 40 × 30 70 Average of all numbers = 240 7 Average of all numbers = 34 2 7
Second method to find the required average ,
Here, n1 = 30, a1 = 40
n2 = 40, a2 = 30∴ Average = n1a1 + n2a2 n1 + n2 ∴ Average = 30 × 40 + 40 × 30 70 Average = 240 7 Average = 34 2 7
- A library has an average number of 510 visitors on Sunday and 240 on other days. The average number of visitors per day in a month of 30 days beginning with Sunday is :
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That month will have 5 sundays.
∴ Required average = 5 × 510 + 25 × 240 40 Required average = 2550 + 6000 30 Required average = 8550 = 285 30
Second method to find the required average ,
Here,
n1 = 5, a1 = 510
n2 = 25, a2 = 240∴ Average = n1a1 + n2a2 n1 + n2
Correct Option: A
That month will have 5 sundays.
∴ Required average = 5 × 510 + 25 × 240 40 Required average = 2550 + 6000 30 Required average = 8550 = 285 30
Second method to find the required average ,
Here,
n1 = 5, a1 = 510
n2 = 25, a2 = 240∴ Average = n1a1 + n2a2 n1 + n2 Average = 5 × 510 + 25 × 240 40 Average = 2550 + 6000 30 Average = 8550 = 285 30