Network theory miscellaneous

Network theory miscellaneous

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Network Theory

Network Elements and the Concept of Circuit
Network theory miscellaneous
  1. For the circuit shown below, V = 30V. Find R—










  1. View Hint View Answer Discuss in Forum

    The given circuit

    The current in 200Ω resistance

    I200Ω = I400Ω =
    – 30V
    		=
    1
    		A = 50mA
    600Ω20

    Current in RΩ resistance
    IRΩ = 150 – 50 = 100mA
    Now,
    R =
    V
    		=
    30V
    		= 300Ω
    IRΩ100mA

    Hence alternative (B) is the correct choice.

    Correct Option: B

    The given circuit

    The current in 200Ω resistance

    I200Ω = I400Ω =
    – 30V
    		=
    1
    		A = 50mA
    600Ω20

    Current in RΩ resistance
    IRΩ = 150 – 50 = 100mA
    Now,
    R =
    V
    		=
    30V
    		= 300Ω
    IRΩ100mA

    Hence alternative (B) is the correct choice.

Direction: 20 to Q. 25. For the circuit shown below—

  1. The power delivered by 7A current source—








  1. View Hint View Answer Discuss in Forum

    The given circuit can be modified as shown below

    From figure the voltage across terminal B and A
    VA + 5 – 4 + 30 – VB = 0
    or
    VB – VA = 31V
    Since terminal B is positive, it means current delivered by the 7A current source will be positive and given by
    Pdelivered = 7 × 31 = 217W

    Correct Option: B

    The given circuit can be modified as shown below

    From figure the voltage across terminal B and A
    VA + 5 – 4 + 30 – VB = 0
    or
    VB – VA = 31V
    Since terminal B is positive, it means current delivered by the 7A current source will be positive and given by
    Pdelivered = 7 × 31 = 217W

  1. The power delivered by 4V source—








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    From figure given in solution 21:
    Current in branch BC is 9A. Since the current is entering at the negative terminal, therefore the power delivered by the 4V source is positive
    Pdelivered = VI = 4 × 9 = 36W

    Correct Option: A

    From figure given in solution 21:
    Current in branch BC is 9A. Since the current is entering at the negative terminal, therefore the power delivered by the 4V source is positive
    Pdelivered = VI = 4 × 9 = 36W

  1. The power absorbed by 5Ω resistor—








  1. View Hint View Answer Discuss in Forum

    From figure given in solution 21, we conclude that current passing through 5Ω resistor is 1A. So power absorbed by 5Ω resistor
    Pabsorbed = I2R = 12 × 5 = 5W.

    Correct Option: A

    From figure given in solution 21, we conclude that current passing through 5Ω resistor is 1A. So power absorbed by 5Ω resistor
    Pabsorbed = I2R = 12 × 5 = 5W.

  1. The value of voltage Vx for the circuit shown below—










  1. View Hint View Answer Discuss in Forum

    The given circuit:

    Applying potential divider rule

    Vx = 9V ×
    (18 + 3)
    (18 + 3 + 6)

    or
    Vx = 9 ×
    21
    		= 7V.
    27

    Correct Option: A

    The given circuit:

    Applying potential divider rule

    Vx = 9V ×
    (18 + 3)
    (18 + 3 + 6)

    or
    Vx = 9 ×
    21
    		= 7V.
    27