Engineering Mathematics Miscellaneous


Engineering Mathematics Miscellaneous

Engineering Mathematics

  1. The inverse Laplace transform of the function
    F (s) =
    1
    is given by
    s(s + 1)









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    L-1
    1
    =
    1
    -
    1
    s(s + 1)ss + 1

    L-1
    1
    -
    1
    = 1 - e-t
    ss + 1

    Correct Option: D

    L-1
    1
    =
    1
    -
    1
    s(s + 1)ss + 1

    L-1
    1
    -
    1
    = 1 - e-t
    ss + 1


  1. The inverse Laplace transform of 1/(s2 + s) is









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    1
    =
    1
    =
    1
    -
    1
    (s2 + s)s(s + 1)s(s + 1)

    Correct Option: C

    1
    =
    1
    =
    1
    -
    1
    (s2 + s)s(s + 1)s(s + 1)



  1. Evaluation of ∫42 x3 dx using a 2-equal-segment trapezoidal rule gives value of _______.









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    Trapezoidal Rule, h = 1

    =
    1
    [ (23 + 43) + 4(33) ]
    2

    =
    1
    [ 8 + 64 + 54 ] = 63
    2

    Correct Option: A

    Trapezoidal Rule, h = 1

    =
    1
    [ (23 + 43) + 4(33) ]
    2

    =
    1
    [ 8 + 64 + 54 ] = 63
    2


  1. P(0, 3), Q(0.5, 4) and R(1, 5) are three points on the curve defined by f(x). Numerical integration is carried out using both Trapezoidal rule and Simpson's rule within limits x = 0 and x = 1 for the curve. The difference between the two results will be









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    By Trapezoidal rule

    =
    0.5
    [ (3 + 5) + 2(4) ] = 4
    2

    By Simpson rule

    =
    0.5
    [ (3 + 5) + 4(4) ] = 4
    3

    Difference between these two results will be 0.

    Correct Option: A


    By Trapezoidal rule

    =
    0.5
    [ (3 + 5) + 2(4) ] = 4
    2

    By Simpson rule

    =
    0.5
    [ (3 + 5) + 4(4) ] = 4
    3

    Difference between these two results will be 0.



  1. The error in numerically computing the integral ∫π0 (sinx + cosx) dx using the trapezoidal rule with three intervals of equal length between 0 and π is _________.









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    = 2
    Error = Exact value – Approx Value
    = 2 – 1.8137 = 0.1863

    Correct Option: B



    = 2
    Error = Exact value – Approx Value
    = 2 – 1.8137 = 0.1863