Home » Aptitude » Speed, Time and Distance » Question
  1. A student starting from his house walks at a
    speed of 2
    1
    km/hour and reaches his
    2
    school 6 minutes late. Next day starting at
    the same time he increases his speed by 1 km/hour and reaches 6 minutes early. The distance between the school and his house is
    1. 4 km
    2. 3
      1
      km
      2
    3. 1
      3
      km
      4
    4. 6 km
Correct Option: C

Distance between school and house = x km (let)

Time =
Distance
Speed

According to the question,
x
x
=
6 + 6
=
1
5/27/2605

(Difference of time = 6 + 6 =12 minutes)
⇒ 
2x
2x
=
1
575

⇒ 
14x − 10x
=
1
4x
=
1
355355

⇒ 4x =
35
= 7
5

⇒  x =
7
= 1
3
km.
44


Second Method :
Here, S1 = 2
1
, t1 = 6
2

S2 = 3
1
, t2 = 6
2

Distance =
(S1 × S2)(t1 + t2)
S2 − S1

=
5
×
7
(6 + 6)
22
7
-
5
22

=
35
×
12
460

=
7
= 1
3
km
44


Your comments will be displayed only after manual approval.