A train, with a uniform speed, crosses a platform, 162 metres

A train, with a uniform speed, crosses a platform, 162 metres long, in 18 seconds and another platform, 120 metres long, in 15 seconds. The speed of the train is

Let the Length of the train be x

Then,	x + 162	=	x + 120
	18		15

(Speed of the train)

⇒	x + 162	=	x + 120
	6		5

⇒ 6x + 720 = 5x + 810
⇒ x = 810 – 720 = 90

∴ Speed of the train =	90 + 162	m/sec.
	18

=	252	×	18	kmph
	18		5

= 50.4 kmph