If a man walks at the rate of 5 km/hour, he misses a train

If a man walks at the rate of 5 km/hour, he misses a train by 7 minutes. However if he walks at the rate of 6 km/hour, he reaches the station 5 minutes before the arrival of the train. The distance covered by him to reach the station is

Let the required distance be x km.
Difference of time = 7 + 5 = 12

minutes =	1	hour
	5

Time =	Distance
	Speed

According to the question,

x	−	x	=	1
5	−	6	=	5

⇒	6x − 5x	=	1
	30		5

⇒	x	=	1
	30		5

⇒ x =	30	= 6 km.
	5