A train 150m long passes a km stone in 30 seconds and another

A train 150m long passes a km stone in 30 seconds and another train of the same length travelling in opposite direction in 10 seconds. The speed ot the second train is :

∴ Speed of train =	150	= 5 m/sec.
	30

Speed of train B = x m/sec.
Relative speed = (5+x) m/sec.
∴ Length of both trains = Relative speed × Time
⇒ 300 = (5 + x) × 10

⇒ 5 + x =	300	= 30
	10

⇒ x = 30 – 5 = 25 m/sec.

=		25 × 18		kmph.
		5

= 90 kmph.