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  1. Two trains start from station A and B and travel towards each other at speed of 16 miles/ hour and 21 miles/ hour respectively. At the time of their meeting, the second train has travelled 60 miles more than the first. The distance between A and B (in miles) is :
    1. 444
    2. 496
    3. 333
    4. 540
Correct Option: A

Let the trains meet after t hours
Then, 21t – 16t = 60
⇒  5t = 60 ⇒ t = 12 hours
∴  Distance between A and B
= (16 + 21) × 12
= 37 × 12 = 444 miles
Second Method :
Here, a = 21, b = 16, d = 60

Distance between A and B =
a + b
× d
a − b

=
21 + 16
× 60
21 − 16

=
37
× 60
5

= 37 × 12 = 444 miles



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