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  1. P and Q starting simultaneously from two different places proceed towards each other at a speed of 20 km/hour and 30 km/hour respectively. By the time they meet each other. Q has covered 36 km more than that of P. The distance (in km.) between the two places is
    1. 144
    2. 162
    3. 180
    4. 108
Correct Option: C

Let P and Q meet after t hours.
Distance = speed × time
According to the question,
30t – 20t = 36
⇒  10t = 36

⇒  t =
36
= 3.6 hours
10

∴  Distance between P and Q
= 30t + 20t
= 50t = (50 × 3.6) km.
= 180 km.

Second Method :
Here, a = 30, b = 20, d = 36
Required distance =
a + b
× d
a − b

=
30 + 20
× 36
30 − 20

=
50
× 36 = 180 km
10


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