A train running at 7 its own speed reached a place 11in

A train running at 7 its own speed reached a place
11
in 22 hours. How much time could be saved if the train would run at its own speed?

Since the train runs at 7/11 of its own speed, the time it takes is 11/7 of its usual speed.
Let the usual time taken be t hours.

Then we can write,	11	t = 22
	7

∴ t =	22 × 7	= 14 hours
	11

Hence, time saved
= 22 – 14 = 8 hours