Walking at3of his usual speed,4 a man is 11hours late.

Time and speed are inversely proportional.

∴	4	of usual time –usual time
	3

=	3
	2

⇒	1	× usual time =	3
	3		2

∴ Usual time =	3 × 3	=	9
	2		2

= 4	1	hours
	2

Second Method :

Here, A = 3, B = 4, t =	3
	2

Usual time =	A	× time
	Diff. of A and B

=	3	×	3
	(4 − 3)		2

= 4	1	hrs.
	2