Home » Aptitude » Speed, Time and Distance » Question
  1. A student rides on bicycle at 8 km/hour and reaches his school 2.5 minutes late. The next day he increases his speed to 10 km/ hour and reaches school 5 minutes early. How far is the school from his house ?
    1. 5
      km
      8
    2. 8 km
    3. 5 km
    4. 10 km
Correct Option: C

Let x km. be the required distance.
Difference in time = 2.5 + 5 = 7.5 minutes

=
7.5
hrs. =
1
hrs.
608

Now, 
x
x
=
1
8108

⇒ 
5x − 4x
=
1
408

⇒  x =
40
= 5 km.
8


Second Methdod :
Here, S1 = 8, t1 = 2.5
S2 = 10, t2 = 5
Distance =
(S1 ×S2)(t1 + t2)
S2 −S1

=
(8 × 10)(2.5 + 5)
10 − 8

= 40 ×
7.5
= 5 km
60



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