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					 Two men A and B start walking simultaneously from P to Q, a distance of 21 kms, at the speed of 3 km and 4 km an hour respectively. B reaches Q, returns immediately and meets A at R. Find the distance from P to R.
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                        - 22 km
- 20 km
- 16 km
- 18 km
 
Correct Option: D
Let A and B meet after time t hours.
Distance covered by A in t hours = 3 t km.
Distance covered by B in t hours = 4 t km.
Total distance covered by A and B = (3t + 4t) km = 7 t km.
From the diagram we can see that the total distance covered by A and B is equal to twice the distance between P and Q.
∴  7t = 2 × 21
| t = | = 6 hours | |
| 2 | 
Distance PR = 6 × 3 = 18 km.
 
	