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  1. Find the sum of 1 −
    1
    		 + 1 −
    2
    		 + 1 −
    3
    		 + .....1 −
    n
    n + 1n + 1n + 1n + 1
    1. n
    2. 1
      		n
      2
    3. (n + 1)
    4. 1
      		(n + 1)
      2
Correct Option: B

1 −
1
 + 1 −
2
 + 1 −
3
 + .....1 −
n
n + 1n + 1n + 1n + 1

= n −
1
 +
2
 +
3
 + ....+
n
n + 1n + 1n + 1n + 1

= n −
1 + 2 + 3 +....+ n
n + 1

= n −
n(n + 1)
 = n −
n
 =
n
 =
1
n
2(n + 1)222


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