Home » Aptitude » Simplification » Question
  1. (1132 + 1152 + 1172 – 113 × 115 – 115 × 117 – 117 × 113) is equal to
    1. 0
    2. 4
    3. 8
    4. 12
Correct Option: D

a2 + b2 + c2 – ab – bc – ac

=
1
(2a2 + 2b2 + 2c2 – 2ab – 2bc – 2ac)
2

=
1
[(a − b)2 + (b − c)2 + (c − a)2 ]
2

=
1
[(113 − 115)2 + (115 − 117)2 + (117 − 113)2 ]
2

Where, a = 113, b = 115, c = 117.
=
1
[( − 2)2 + (− 2)2 + 42 ]
2

=
1
(4 + 4 + 16)
2

=
1
× 24 = 12
2



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