Correct Option: B

Let us assume the three consecutive natural numbers be P, P + 1 and P + 2.
∴  According to the given question,
P² + (P + 1)² + (P + 2)² = 2030
   P² + P² + 2P + 1 + P² + 4P + 4 = 2030
⇒    3P² + 6P + 5 = 2030
⇒    3P² + 6P − 2025 = 0
⇒    P² + 2P – 675 = 0
⇒    P² + 27P – 25P – 675 = 0
⇒    P (P + 27) – 25 (P+ 27) = 0
⇒    (P – 25) (P + 27) = 0
∴  P = 25 and – 27
∴  Required number = P + 1 = 25 + 1 = 26