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  1. If 100.3010 = 2, then find the value of log0.125 125. ?
    1. 699 / 301
    2. - 699 / 301
    3. - 1
    4. - 2
Correct Option: B

Exp. = log0.125125 = log2-3 53 = - 3/3log25 = -log25
∵ 100.3010 = 2
⇒ log102 = 0.3010
∵ log105 = log1010/2 = log1010-log102
= 1-0.3010 = 0.6990
∴ -log25 = - log105 / log102
= - 0.6990 / 0.3010 = - 699/301



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