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when the interest being compounded annually, isThe compound interest on ₹ 6,000 at 10% per annum for 1 1 years, 2
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- ₹ 910
- ₹ 870
- ₹ 930
- ₹ 900
Correct Option: C
Here , A = ? , P = ₹ 6,000 , R = 10% , T = ( 3 / 2 ) years
Amount = 6000 | ![]() | 1 + | ![]() | × | ![]() | 1 + | ![]() | ||
100 | 100 |
⇒ Amount = 6000 × | × | = ₹ 6930 | ||
10 | 20 |
Second Method to solve this question :
Here, t = nF
A = P | ![]() | 1 + | ![]() | n | ![]() | 1 + | ![]() | ||
100 | 100 |
∴ A = ₹ 6930
CI = Amount - Principal
∴ CI = ₹ (6930 – 6000) = ₹ 930