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The time in which ₹ 80,000 amounts to ₹ 92,610 at 10% p.a. compound interest, interest being compounded semi annually is :
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1 1 years 2 - 2 years
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2 1 years 2 - 3 years
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Correct Option: A
Given Here , Amount ( A ) = ₹ 92,610 , P = ₹ 80,000 , Rate ( R ) = 10% p.a. , Time = t half year and R = 5% per half year
∴ A = P | ![]() | 1 + | ![]() | T | |
100 |
⇒ 92,610 = 80,000 | ![]() | 1 + | ![]() | T | |
100 |
⇒ | = | ![]() | 1 + | ![]() | T | ||
80000 | 100 |
⇒ | = | ![]() | ![]() | T | ||
8000 | 20 |
⇒ | ![]() | ![]() | 3 | = | ![]() | ![]() | T | ||
20 | 20 |
⇒ T = 3 half years or 1 | years | |
2 |