-
A sum of ₹ 3,200 invested at 10% p.a. compounded quarterly amounts to 3,362. Compute the time period.
-
-
1 year 2 - 1 year
- 2 years
-
3 year 4
-
Correct Option: A
Here , Amount ( A ) = ₹ 3,362 , P = ₹ 3,200 , Rate ( R ) = 10% , Time = quarterly = 4t
A = P | ![]() | 1 + | ![]() | T | |
100 |
Interest is compounded quarterly ,
3,362 = 3200 | ![]() | 1 + | ![]() | 4t | |
400 |
⇒ | = | ![]() | 1 + | ![]() | 4t | ||
3200 | 40 |
⇒ | = | ![]() | ![]() | 4t | ||
1600 | 40 |
⇒ | ![]() | ![]() | 2 | = | ![]() | ![]() | 4t | ||
40 | 40 |
⇒ 4t = 2 ⇒ t = | year | |
2 |