-
the simple interest on the same sum at the same rate for the same period of time isIf the compound interest on a sum for 2 years at 12 1 p.a is ₹ 510, 2
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- ₹ 400
- ₹ 450
- ₹ 460
- ₹ 480
Correct Option: D
Suppose Principal = ₹ P
Given in question , Compound Interest ( CI ) = ₹ 510 , Rate ( R ) = ( 25 / 2 )% , Time = 2 years
∴ C.I. = P | ![]() | ![]() | 1 + | ![]() | T | − 1 | ![]() | |
100 |
⇒ 510 = P | ![]() | ![]() | 1 + | ![]() | 2 | − 1 | ![]() | |
200 |
⇒ 510 = P | ![]() | ![]() | 1 + | ![]() | 2 | − 1 | ![]() | |
8 |
⇒ 510 = P | ![]() | ![]() | ![]() | 2 | − 1 | ![]() | |
8 |
⇒ 510 = P | ![]() | − 1 | ![]() | |
64 |
⇒ 510 = P | ![]() | ![]() | |
64 |
⇒ 510 = | |
64 |
⇒ P = | = ₹ 1920 | |
17 |
∴ S.I.= | |
100 |
S.I. = | = ₹ 480 | |
100 × 2 |
With the help of given formula :
Here, C.I. = ₹ 510 , R = 12 | %, S.I. = ? | |
2 |
C.I.= S.I. | ![]() | 1 + | ![]() | |
200 |
510 = S.I. | ![]() | 1 + | ![]() | |
400 |
510 = S.I. | ![]() | ![]() | |
400 |
S.I. = | = ₹ 480 | |
425 |