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A sum of money placed at compound interest doubles itself in 5 years. In how many years, it would amount to eight times of itself at the same rate of interest ?
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- 10 years
- 15 years
- 7 years
- 20 years
Correct Option: B
Let the Principal be P and rate of interest be r%.
∴ 2 P = P | ![]() | 1 + | ![]() | 2 | |
100 |
⇒ 2 = | ![]() | 1 + | ![]() | 5 | ...(i) | |
100 |
On cubing both sides, we get
8 = | ![]() | 1 + | ![]() | 15 | |
100 |
On multiplying by P both sides ,
8P = P | ![]() | 1 + | ![]() | 15 | |
100 |
∴ The sum will be 8 times in 15 years. i.e., Time = 15 years
We can find required answer with the help of given formula :
Here, m = 2, t = 5 years
It becomes 8 times = 23 times
in t × n = 5 × 3 = 15 years