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A sum of money becomes double in 3 years at compound interest compounded annually. At the same rate, in how many years will it become four times of itself ?
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- 4 years
- 6 years
- 6.4 years
- 7.5 years
Correct Option: B
Given , Time = 3 years , Rate = R%
Let Principal be ₹ P and Amount = ₹ 2P
Using the given formula
A = P | 1 + | T | |||
100 |
According to question ,
⇒ 2 = 1 | 1 + | 3 | |||
100 |
On squaring both sides and multiplying by P
4P = P | 1 + | 6 | |||
100 |
∴ Time = 6 years
Second Method to solve this question :
Here, p = 2, n1 = 3
q = 4, n2 = ?
∴ p1/n1 = q1/n2
⇒ 21/3 = 41/n2
21/3 = (22)1/n2
⇒ 21/3 = 22/n2
Equating powers of 2 on both sides , we get
= | ||
3 | n2 |
∴ n2 = 6 Years