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A sum of money becomes 1.331 times in 3 years as compound interest. The rate of interest is
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- 8%
- 7.5%
- 10%
- 50%
Correct Option: C
As per the given in question ,
Time = 3 years , Rate = R%
Suppose principal = ₹ 1000 , then amount = ₹ 1331
∴ A = P | ![]() | 1 + | ![]() | T | |
100 |
⇒ 1331 = 1000 | ![]() | 1 + | ![]() | 3 | |
100 |
⇒ | = | ![]() | 1 + | ![]() | 3 | ||
1000 | 100 |
⇒ | ![]() | ![]() | 3 | = | ![]() | 1 + | ![]() | 3 | ||
10 | 100 |
⇒ 1 + | = | ||
100 | 10 |
⇒ | = | ||
100 | 10 |
⇒ R = | × 100 = 10% | |
10 |
Second Method to solve this question :
Here, n = 1.331, t = 3 years
R% = (n1/t − 1) × 100%
R% = [(1.331)1/3 − 1] × 100%
R% =[1.1 − 1] × 100%
R% = 0.1 × 100% = 10%