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An amount of money at compound interest grows up to ₹ 3,840 in 4 years and up to ₹ 3,936 in 5 years. Find the rate of interest.
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- 2.5%
- 2%
- 3.5%
- 2.05%
Correct Option: A
Here , A1 = ₹ 3,840 , T1 = 4 years and A2 = ₹ 3,936 , T2 = 5 years
Using the given formula , we have
A = P | ![]() | 1 + | ![]() | T | |
100 |
∴ 3840 = P | ![]() | 1 + | ![]() | 4 | ..... (i) | |
100 |
3936 = P | ![]() | 1 + | ![]() | 5 | ..... (ii) | |
100 |
Dividing equation (ii) by equation (i),
= 1 + | ||
3840 | 100 |
⇒ | = | − 1 | ||
100 | 3840 |
= | = | ||
3840 | 3840 |
⇒ R = | × 100% = 2.5% | |
3840 |
Second Method tom solve this question :
Here, b – a = 5 – 4 = 1 and B = Rs. 3,936, A = Rs. 3,840
R% = | ![]() | − 1 | ![]() | × 100% | |
A |
R% = | ![]() | − 1 | ![]() | × 100% | |
3840 |
R% = | ![]() | ![]() | × 100% | |
3840 |
R% = | × 100% | |
3840 |
R% = | % = 2.5% | |
4 |