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A sum of money invested at compound interest amounts to ₹ 650 at the end of first year and ₹ 676 at the end of second year. The sum of money is :
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- ₹ 600
- ₹ 540
- ₹ 625
- ₹ 560
Correct Option: C
As per the given in question ,
Interest on ₹ 650 for 1 year = 676 – 650 = ₹ 26
So, r = | × 100 | |
650 |
⇒ r = 4% per annum
P = | ||||
![]() | 1 + | |||
![]() | t | |||
100 |
P = | ||||
![]() | 1 + | |||
![]() | 1 | |||
100 |
= | = 650 × | = ₹ 625 | ||
( 26/25 ) | 26 |
Using the given formula :
Here, b – a = 1 , B = Rs 676, A = ₹ 650
R% = | ![]() | − 1 | ![]() | × 100% | |
A |
R% = | ![]() | − 1 | ![]() | × 100% | |
650 |
R% = | ![]() | ![]() | × 100% | |
650 |
R% = | × 100% | |
650 |
R% = | = 4% | |
25 |
Amount = P | ![]() | 1 + | ![]() | 1 | |
100 |
650 = P | ![]() | 1 + | ![]() | |
100 |
⇒ P = | = ₹ 625 | |
104 |
Note : A sum at a rate of interest compounded yearly becomes ₹ A, in n years and ₹ A2 in (n + 1) years,
then P = A1 | ![]() | ![]() | n | |
A2 |