-
A sum becomes ₹ 4500 after two years and ₹ 6750 after four years at compound interest. The sum is
-
- ₹ 4000
- ₹ 2500
- ₹ 3000
- ₹ 3050
Correct Option: C
Given in question , A1 = ₹ 4500 , T1 = 2 years and A2 = ₹ 6750 , T2 = 4 years
Suppose principal = P
P | ![]() | 1 + | ![]() | 2 | = 4500 ..... (i) | |
100 |
P | ![]() | 1 + | ![]() | 4 | = 6750 ..... (ii) | |
100 |
On dividing equation (ii) by equation (i), we get
![]() | 1 + | ![]() | 2 | = | ||
100 | 4500 |
From equation (i), we get
P × | = 4500 | |
4500 |
⇒ P = | = ₹ 3,000 | |
6750 |
Second Method to solve this question :
Here, b – a = 4 – 2 = 2 and B = ₹ 6750, A = ₹ 4500
R% = | ![]() | ![]() | ![]() | 1/2 | − 1 | ![]() | × 100% | |
A |
R% = | ![]() | ![]() | ![]() | 1/2 | − 1 | ![]() | × 100% | |
4500 |
R% = | ![]() | ![]() | ![]() | 1/2 | − 1 | ![]() | × 100% | |
2 |
⇒ | ![]() | ![]() | 1/2 | = 1 + | ||
2 | 100 |
⇒ | = | ![]() | 1 + | ![]() | 2 | ||
2 | 100 |
Using formula ,
A = P | ![]() | 1 + | ![]() | 2 | |
100 |
4500 = P × | |
2 |
P = ₹ 3000