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A man gave 50% of his savings of ₹ 84,100 to his wife and divided the remaining sum among his two sons A and B of 15 and 13 years of age respectively. He divided it in such a way that each of his sons, when they attain the age of 18 years, would receive the same amount at 5% compound interest per annum. The share of B was
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- ₹ 20,000
- ₹ 20,050
- ₹ 22,000
- ₹ 22,050
Correct Option: A
Amount given to sons = 84100 × | = ₹ 42050 | |
2 |
Let Amount given to B = ₹ y
∴ Amount given to A = ₹ (42050 – y)
A = P | ![]() | 1 + | ![]() | T | |
100 |
⇒ (42050 – y ) | ![]() | 1 + | ![]() | 3 | = y | ![]() | 1 + | ![]() | 5 | ||
100 | 100 |
⇒ (42050 – y ) = y | ![]() | 1 + | ![]() | 2 | |
100 |
⇒ (42050 – y ) = y | ![]() | 1 + | ![]() | 2 | |
100 |
⇒ (42050 – y ) = y | ![]() | 1 + | ![]() | 2 | |
20 |
⇒ 42050 – y = y | ![]() | ![]() | 2 | |
20 |
⇒ 42050 – y = | |
400 |
⇒ 42050 = | + y | |
400 |
⇒ 42050 = | |
400 |
⇒ 42050 = | |
400 |
⇒ 841 y = 42050 × 400
⇒ y = | = ₹ 20,000 | |
841 |