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A sum amounts to ₹ 9680 in 2 years and to ₹ 10648 in 3 years compounded annually. Find the principal and the rate of interest per annum.
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- 12% ; ₹ 7500
- 10% ; ₹ 8000
- 11% : ₹ 11000
- None of these
Correct Option: B
Let Principal = P , Rate = r% p.a.
Here , A1 = ₹ 9680 , t1 = 2 years , A2 = ₹ 10648 , t2 = 3 years
Interest on ₹ 9680 for 1 year = 10648 – 9680 = ₹ 968
∴ r = | = 10% | |
9680 |
Using the given formula,
A = P | ![]() | 1 + | ![]() | t | |
100 |
we get ,
9680 = P | ![]() | 1 + | ![]() | 2 | = P | ![]() | ![]() | 2 | ||
100 | 10 |
⇒ P = 9680 × | × | = 8000 | ||
11 | 11 |
∴ Principal = ₹ 8000.