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  1. The equation logax + loga (1+x)=0 can be written as ?
    1. x2 + x - 1 = 0
    2. x2 + x + 1 = 0
    3. x2 + x - e = 0
    4. x2 + x + e = 0
Correct Option: A

logax + loga(1+x) = 0
⇒ logax (x+1) = loga1 (since log 1 = 0)
⇒ x(x +1) = 1
∴ x2 + x - 1 = 0


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