A candidate secured 30% marks in an examination and failed

A candidate secured 30% marks in an examination and failed by 6 marks. Another secured 40% marks and got 6 marks more than the bare minimum to pass. The maximum marks are

Difference of percentage
= (40 – 30)% = 10%
Difference of marks = 6 + 6= 12
∵ 10% of total marks = 12

Total marks =	12 × 100	= 120
	10

Aliter : Using Rule 22,
Here, m = 30%, n = 40%,
p = 6, q = 6.
∴ Maximum Marks

=	100	× (p + q)
	(n - m)

=	100	× (6 + 6)
	(40 - 30)

=	100	× 12 = 120
	10