X has twice as much money as that of Y and Y has 50% more

X has twice as much money as that of Y and Y has 50% more money than that of Z. If the average money of all of them is 110, then the money, which X has, is

Let z have x

∴ Money with Y =	3	x and
	2

Money with X = 3x

∴ 3x +	3x	+ x = 3 × 110
	2

⇒	6x + 3x + 2x	= 330
	2

⇒ 11 x = 2 × 330

⇒ x =	2 × 330	= 60
	11

∴ Money with
X = 3x = ₹(3×60) = ₹ 180