Correct Option: D
As per the given in question ,
Principal + interest for 8 years = ₹ 2900... (i)
Principal + interest for 10 years = ₹ 3000 ... (ii)
Subtracting equation (i) from (ii)
Interest for 2 years = ₹ 100
| ∴ Interest for 8 years = | 100 | × 8 = ₹ 400 |
| 2 |
From equation (i),
Principal = ₹ (2900 – 400) = ₹ 2500
| ∴ Rate = | S.I × 100 |
| Principal × Time |
Second method to solve this question : Here , A
2 = ₹ 3000 , T
1 = 8 years , A
1 = ₹ 2900 , T
2 = 10 years
| R = |  | A1 - A2 |  | × 100 |
| A2T1 - A1T2 |
| R = | | 2900 - 3000 | | × 100 |
| 3000 × 8 - 2900 × 10 |
| R = | | - 100 | | × 100 |
| 24000 - 29000 |
| R = | - 100 | × 100 = 2% |
| - 5000 |
