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The diagonal of a square is 4√2 cm. The diagonal of another square whose area is double that of the first square is :
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- 8√2 cm
- 16 cm
- √32 cm
- 8 cm
- 8√2 cm
Correct Option: D
Using Rule 10, Side of the first square
| = | × 4√2 = 4cm | |
| √2 |
Its area = (4)² = 16 cm².
∴ Area of second square = 2 × 16 = 32 cm².
Its side = √32 = 4 √2cm.
∴ Required diagonal = √2 × 4√2 = 8 cm
