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The diagonal of a square A is (a+b). The diagonal of a square whose area is twice the area of square A, is
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- 2 (a+b)
- 2 (a+b)²
- √2(a+b)
- √2(a-b)
- 2 (a+b)
Correct Option: C
Using Rule 10,
| Area of the square A = | |
| 2 |
| = | |
| 2 |
| Area of the new square = | × 2 = (a + b)² | |
| 2 |
⇒ Side = (a + b)
∴ Diagonal = √2 × side = √2 (a + b)
