Home » Aptitude » Mensuration » Question

Mensuration

Easy Questions
Moderate Questions
Difficult Questions

Aptitude

Simplification
Number System
Fractions
Elementary Algebra
LCM and HCF
Approximation
Unitary Method
Linear Equation
Quadratic Equation
Discount
Average
Surds and Indices
Percentage
Square root and cube root
Order of Magnitude
Work and Wages
Odd Man Out and Series
Algebra
Profit and Loss
Stocks and Shares
True Discount
Ratio, Proportion
Partnership
Alligation or Mixture
Time and Work
Pipes and Cistern
Speed, Time and Distance
Problem on Trains
Height and Distance
Banker's Discount
Boats and Streams
Races and games
Problems on Ages
Clocks and Calendars
Simple interest
Compound Interest
Sets and Functions
Area and Perimeter
Volume and Surface Area of Solid Figures
Sequences and Series
Plane Geometry
Logarithm
Probability
Permutation and Combination
Statistics
Mensuration
Trigonometry
Aptitude miscellaneous
  1. The sides of a triangle are 16 cm, 12 cm and 20 cm. Find the area.
    1. 64 cm²
    2. 112 cm²
    3. 96 cm²
    4. 81 cm²
Correct Option: C

Using Rule 2 and 3,
Semi–perimeter

S =
16 + 12 + 20
2

=
48
 = 24 cm
2

Area of triangle
= √s(s - a)(s -b)(s - c)
= √24(24 - 16)(24 - 12)(24 - 20)
= √24 × 8 × 12 × 4 = 96 sq.cm


Your comments will be displayed only after manual approval.