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ABC is an equilateral triangle. P and Q are two points on AB and AC respectively such that PQ || BC . If PQ = 5 cm, then area of ∆APQ is :
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25 sq. cm. 4 -
25 sq. cm. √3 -
25√3 sq. cm. 4 - 25√3 sq. cm
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Correct Option: C
Using Rule 6,
PQ Ω BC
∠APQ = ∠ABC = 60°
∠AQP = ∠ACB = 60°
∴ Area of ∆APQ = | × (PQ)² | |
4 |
= | × 5² = | sq. cm. | ||
4 | 4 |