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C1 and C2 are two concentric circles with centre at O. Their radii are 12 cm. and 3 cm. respectively. B and C are the point of contact of two tangents drawn to C2 from a point A lying on the circle C1. Then, the area of the quadrilateral ABOC is
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9√15 sq. cm. 2 - 12√15 sq. cm.
- 9√15 sq. cm.
- 6√15 sq. cm.
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Correct Option: A
AB = AC = tangents from the same point
OB = OC = 3 cm
OA = 12 cm
∠ABO = 90°
∴ AB = √12² - 3²
= √15 × 9 = 3√15
∆ OAB = | OB × AB | |
2 |
∴ | × 3 × 3√15 = | ||
2 | 2 |
∴ Area of OABC = | sq.cm. | |
2 |