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From a point P which is at a distance of 13 cm from centre O of a circle of radius 5 cm, in the same plane, a pair of tangentsPQ and PR are drawn to the circle. Area of quadrilateral PQOR is
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- 65 cm²
- 60 cm²
- 30 cm²
- 90 cm²
- 65 cm²
Correct Option: B
∠OQP = ∠ORP = 90°
PQ = √OP² - OQ²
= √13⊃ - 5⊃ = 12
∴ Area of PQOR = 2 × ∆OPQ
= 2 × | × 5 × 12 | |
2 |
= 60 sq. cm