ABC is a right angled triangle. B being the right angle.

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ABC is a right angled triangle. B being the right angle. Mid-points of BC and AC are respectiveely B' and A'. Area of ∆A'B'C' is

Using Rule 1,

In ∆ABC and ∆A'B'C A'B' || AB
∠B' = ∠B, ∠A' = ∠A
∴ ∆ABC ~ ∆A'B'C

∆ A'B' =	1	AB.
	2

∴ Area of ∆A'B'C =	1	× B'C × A'B'
	2

=	1	×	1	BC ×	1	AB
	2		2		2

=	1	×	1	(BC × AB)
	4		2

=	1	× Area of ∆ABC
	4

1	× area of ∆ABC
2

2	× area of ∆ABC
3

1	× area of ∆ABC
4

1	× area of ∆ABC
8