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A wire of length 44 cm is first bent to form a circle and then rebent to form a square. The difference of the two enclosed areas is
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- 44 cm²
- 33 cm²
- 55 cm²
- 66 cm²
- 44 cm²
Correct Option: B
Using Rule 14,
Circumference of circle
= 2πr = 44
⇒ 2 × | × r = 44 | |
7 |
⇒ r = | = 7cm. | |
2 × 22 |
Area of circle = πr²
= | × 7 × 7 = 154 sq.cm. | |
7 |
Perimeter of square = 44 cm.
Side of square = | = 11 cm. | |
4 |
Area of square = 11 × 11 = 121 sq. cm.
Difference = 154 – 121 = 33 sq. cm.